Integrand size = 27, antiderivative size = 143 \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=-\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}-\frac {3 e^4 \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{8 d^4} \]
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Time = 0.09 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {864, 849, 821, 272, 65, 214} \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=-\frac {3 e^4 \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{8 d^4}-\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2} \]
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Rule 65
Rule 214
Rule 272
Rule 821
Rule 849
Rule 864
Rubi steps \begin{align*} \text {integral}& = \int \frac {d-e x}{x^5 \sqrt {d^2-e^2 x^2}} \, dx \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}-\frac {\int \frac {4 d^2 e-3 d e^2 x}{x^4 \sqrt {d^2-e^2 x^2}} \, dx}{4 d^2} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}+\frac {\int \frac {9 d^3 e^2-8 d^2 e^3 x}{x^3 \sqrt {d^2-e^2 x^2}} \, dx}{12 d^4} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}-\frac {\int \frac {16 d^4 e^3-9 d^3 e^4 x}{x^2 \sqrt {d^2-e^2 x^2}} \, dx}{24 d^6} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}+\frac {\left (3 e^4\right ) \int \frac {1}{x \sqrt {d^2-e^2 x^2}} \, dx}{8 d^3} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}+\frac {\left (3 e^4\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {d^2-e^2 x}} \, dx,x,x^2\right )}{16 d^3} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}-\frac {\left (3 e^2\right ) \text {Subst}\left (\int \frac {1}{\frac {d^2}{e^2}-\frac {x^2}{e^2}} \, dx,x,\sqrt {d^2-e^2 x^2}\right )}{8 d^3} \\ & = -\frac {\sqrt {d^2-e^2 x^2}}{4 d x^4}+\frac {e \sqrt {d^2-e^2 x^2}}{3 d^2 x^3}-\frac {3 e^2 \sqrt {d^2-e^2 x^2}}{8 d^3 x^2}+\frac {2 e^3 \sqrt {d^2-e^2 x^2}}{3 d^4 x}-\frac {3 e^4 \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )}{8 d^4} \\ \end{align*}
Time = 0.18 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.84 \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (-6 d^3+8 d^2 e x-9 d e^2 x^2+16 e^3 x^3\right )}{24 d^4 x^4}-\frac {3 \sqrt {d^2} e^4 \log (x)}{8 d^5}+\frac {3 \sqrt {d^2} e^4 \log \left (\sqrt {d^2}-\sqrt {d^2-e^2 x^2}\right )}{8 d^5} \]
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Time = 0.40 (sec) , antiderivative size = 99, normalized size of antiderivative = 0.69
method | result | size |
risch | \(-\frac {\sqrt {-e^{2} x^{2}+d^{2}}\, \left (-16 e^{3} x^{3}+9 d \,e^{2} x^{2}-8 d^{2} e x +6 d^{3}\right )}{24 d^{4} x^{4}}-\frac {3 e^{4} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{8 d^{3} \sqrt {d^{2}}}\) | \(99\) |
default | \(\frac {-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4 d^{2} x^{4}}+\frac {e^{2} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{2 d^{2} x^{2}}-\frac {e^{2} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )}{2 d^{2}}\right )}{4 d^{2}}}{d}+\frac {e^{4} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )}{d^{5}}+\frac {e^{2} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{2 d^{2} x^{2}}-\frac {e^{2} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )}{2 d^{2}}\right )}{d^{3}}-\frac {e^{3} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{d^{2} x}-\frac {2 e^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{d^{2}}\right )}{d^{4}}+\frac {e \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{3 d^{4} x^{3}}-\frac {e^{4} \left (\sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}+\frac {d e \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{\sqrt {e^{2}}}\right )}{d^{5}}\) | \(477\) |
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Time = 0.26 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.60 \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\frac {9 \, e^{4} x^{4} \log \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{x}\right ) + {\left (16 \, e^{3} x^{3} - 9 \, d e^{2} x^{2} + 8 \, d^{2} e x - 6 \, d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{24 \, d^{4} x^{4}} \]
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\[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\int \frac {\sqrt {- \left (- d + e x\right ) \left (d + e x\right )}}{x^{5} \left (d + e x\right )}\, dx \]
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\[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\int { \frac {\sqrt {-e^{2} x^{2} + d^{2}}}{{\left (e x + d\right )} x^{5}} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 329 vs. \(2 (123) = 246\).
Time = 0.28 (sec) , antiderivative size = 329, normalized size of antiderivative = 2.30 \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\frac {{\left (3 \, e^{5} - \frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} e^{3}}{x} + \frac {24 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{2} e}{x^{2}} - \frac {72 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{3}}{e x^{3}}\right )} e^{8} x^{4}}{192 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{4} d^{4} {\left | e \right |}} - \frac {3 \, e^{5} \log \left (\frac {{\left | -2 \, d e - 2 \, \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |} \right |}}{2 \, e^{2} {\left | x \right |}}\right )}{8 \, d^{4} {\left | e \right |}} + \frac {\frac {72 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} d^{12} e^{5} {\left | e \right |}}{x} - \frac {24 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{2} d^{12} e^{3} {\left | e \right |}}{x^{2}} + \frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{3} d^{12} e {\left | e \right |}}{x^{3}} - \frac {3 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{4} d^{12} {\left | e \right |}}{e x^{4}}}{192 \, d^{16} e^{4}} \]
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Timed out. \[ \int \frac {\sqrt {d^2-e^2 x^2}}{x^5 (d+e x)} \, dx=\int \frac {\sqrt {d^2-e^2\,x^2}}{x^5\,\left (d+e\,x\right )} \,d x \]
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